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386^2-336^2=b^2
We move all terms to the left:
386^2-336^2-(b^2)=0
We add all the numbers together, and all the variables
-1b^2+36100=0
a = -1; b = 0; c = +36100;
Δ = b2-4ac
Δ = 02-4·(-1)·36100
Δ = 144400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144400}=380$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-380}{2*-1}=\frac{-380}{-2} =+190 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+380}{2*-1}=\frac{380}{-2} =-190 $
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